they are present on both sides of the equation, tells you that the reaction does not take place. The fact that all four ions are spectator ions, i.e. All compounds containing sodium, potassium, ammonium, nitrate, nitrite, perchlorate, or acetate are. Apply them in the order listed - once you find a rule that applies, IGNORE the rest. Here's a set of solubility rules you can use. To show that this is the case, you can write the complete ionic equation. A precipitate will be formed if you have two ions that can form a compound that is insoluble in water. So if you start with all four ions present as such in aqueous solution and end up the same way, then you can't say that this reaction will not produce an insoluble solid that can precipitate out of the solution.Ĭonsequently, you can say that this double-replacement reaction does not take place. Potassium sulfate, ammonium nitrate, potassium nitrate and ammonium sulfate are all soluble in water meaning that the ions dissociated in the two separated. Similarly, sodium acetate is soluble because there are no anions that can form an insoluble solid with the sodium cation. Now, the two products that can be formed here are ammonium acetate, #"NH"_ 4"CH"_ 3"COOH"#, and sodium sulfate, #"Na"_ 2"SO"_4#.Īccording to the solubility rules, which you can find listed here, both of these compounds are soluble in water, which implies that they exist as ions in aqueous solution.Īmmonium acetate is soluble because there are no anions that can form an insoluble solid with this cation. Sodium acetate and ammonium sulfate are both soluble ionic compounds, which implies that they exist as ions in aqueous solution. The idea here is that you're mixing two solutions that contain soluble ionic compounds and you're interested in finding out if an insoluble ionic compound can be formed by the reaction.
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